(C) $1$. The reaction $NO + O_2 \rightarrow NO_2$ gives $A = NO_2$.$2$. $NO_2$ exists in equilibrium with its dimer $N_2O_4$,so $D = N_2O_4$.$3$. When

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(C) $1$. The reaction $NO + O_2 \rightarrow NO_2$ gives $A = NO_2$.$2$. $NO_2$ exists in equilibrium with its dimer $N_2O_4$,so $D = N_2O_4$.$3$. When $NO_2$ reacts with aqueous $NaOH$,it undergoes a disproportionation reaction:$2NO_2 + 2NaOH \rightarrow NaNO_3 + NaNO_2 + H_2O$.$4$. Here,$B$ and $C$ are $NaNO_3$ and $NaNO_2$.

Class 12 Chemistry p-Block Elements (Class 12)Nitrogen family

Medium

The mixture of $B$ and $C$ are :
$NO \xrightarrow{O_2} A \rightleftharpoons D$
$A \xrightarrow{NaOH \ (aq.)} [B + C]$

A
$NaNO_2 + HNO_3$
B
$HNO_3 + HNO_2$
C
$NaNO_3 + NaNO_2$
D
$NaNO_3 + HNO_2$

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p-Block Elements (Class 12)

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Nitrogen family

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The mixture of $B$ and $C$ are :$NO \xrightarrow{O_2} A \rightleftharpoons D$$A \xrightarrow{NaOH \ (aq.)} [B + C]$

Similar Questions

Which of the following has the highest number of $P-H$ bonds?

Heating $(NH_4)_2Cr_2O_7$ liberates a gas. The same gas is obtained by:

In the $15^{th}$ group of the periodic table,the elements $N, P, As, Sb$,and $Bi$ are present. As we move from $N$ to $Bi$,how do the oxides with the general formula change?

Which of the following compounds gives $N_2$ gas on thermal decomposition?

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The mixture of $B$ and $C$ are :
$NO \xrightarrow{O_2} A \rightleftharpoons D$
$A \xrightarrow{NaOH \ (aq.)} [B + C]$